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0=4x^2-x-2
We move all terms to the left:
0-(4x^2-x-2)=0
We add all the numbers together, and all the variables
-(4x^2-x-2)=0
We get rid of parentheses
-4x^2+x+2=0
a = -4; b = 1; c = +2;
Δ = b2-4ac
Δ = 12-4·(-4)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{33}}{2*-4}=\frac{-1-\sqrt{33}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{33}}{2*-4}=\frac{-1+\sqrt{33}}{-8} $
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